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Beam Deflection: Sag, Stiffness and the Span That Causes It

Work out how far a beam or tube deflects under load, the second moment of area behind it, and whether it meets the usual L/240 and L/360 limits.

in

Clear distance, support to support. This is the number that dominates everything below — it enters as a cube or a fourth power.

lb

Everything the beam carries between the supports, including its own weight if it matters.

A point load at mid-span is the worst case for the same total weight; spreading it out cuts the sag by nearly half.

A 2×2×⅛ tube has about 40% of the stiffness of solid 2×2 bar — and a quarter of the metal, so per pound it is nearly twice as stiff. That trade is why structures are built from hollow sections.

in

The dimension in the direction of the load — this is the one that matters, because it enters as a cube. A 2×4 on edge is eight times stiffer than flat.

in

Across the load. Ignored for round sections, where the depth is the diameter.

in

For hollow sections only. Doubling it adds more stiffness than a quarter inch of depth — but several times the material, which is why depth is the cheaper cure per pound.

Young’s modulus in psi. Steel is three times as stiff as aluminium, which is why an aluminium section has to be deeper for the same sag.

Deflection at mid-span

0.57596in

PL³ ÷ 48EI for a point load, 5WL³ ÷ 384EI spread out. That is span cubed — doubling the span multiplies the sag eightfold under the same weight.

Second moment of area
0.55176in⁴

The I in the formula, and the whole of what a section shape buys you. It goes with the cube of the depth, which is why depth buys more stiffness per pound of steel than anything else you can change.

Span over deflection
167

How codes express it. L/360 is the usual floor limit, L/240 the general one, and L/180 the loosest thing anyone will sign off.

Does it meet L/360
0

1 means it passes the strict floor limit. Plaster and tile crack at about L/360, which is where that number comes from.

Does it meet L/240
0
The L/360 limit in inches
0.2667in

On a 96 in span. It is a small number, which is why stiffness rather than strength usually picks the beam.

Deflection with a quarter inch more depth
0.43428in

A quarter inch of depth costs almost no material — on a 2×2×⅛ tube it is 7% more steel for 33% more stiffness. Compare it with the wall line below, which buys more stiffness and pays several times as much weight for it.

Deflection with double the wall
0.34866in

Doubling the wall does beat a quarter inch of depth on stiffness — it roughly doubles the section area to do it. Per pound of material the extra depth wins by a wide margin, which is why beams get deeper rather than thicker.

Deflection over half the span
0.072in

An eighth of the sag, for the same load. Adding a post in the middle is worth more than any amount of steel.

Load that would just meet L/360
231lb

The stiffness limit rather than the strength limit — the beam will carry far more than this before it is in any danger, it will simply sag more than a finish can tolerate.

Span that would just meet L/360 at this load
65.3in

Solved the other way. Shortening a span is worth far more than deepening the beam, because the span enters at a higher power.

Deflection if it were aluminium
1.6703in

Aluminium is about a third the stiffness of steel at a third the weight. Section for section it sags three times as far, which is why aluminium beams are deeper.

How to use this calculator

  1. Enter the clear distance from support to support into the Span between supports field.
  2. Input the combined weight carried between those supports into the Total load field.
  3. Select whether the weight sits as a single point in the middle or spreads evenly across the span using How the load sits.
  4. Choose your structural geometry from the Section menu, then fill in the Depth of the section, Width of the section, and wall thickness where requested.
  5. Select your framing material from the Material menu to apply the correct Young's modulus.

Understanding Beam Deflection and Sag

When a weight rests on a structural member, the member bends. Calculating beam deflection reveals just how much that piece will sag under a given load before it ever reaches its breaking point. In real-world construction and fabrication, checking how much will a beam sag prevents cracked drywall, jammed doors, and structural failures long before material strength becomes an issue. Structural codes establish strict limits on this downward movement, most notably the l/360 deflection limit for finished ceilings and the l/240 deflection limit for standard floor framing.

To run these checks, the calculation relies heavily on geometry. Every cross-section possesses a specific second moment of area, often called the moment of inertia, measured in inches to the fourth power. This property quantifies how the cross-sectional shape resists bending. A hollow square tube deflection calculator model demonstrates that shifting material away from the neutral axis toward the outer edges creates an efficient structure with high stiffness relative to its weight.

The Mathematics Behind the Formula

Underneath any reliable beam deflection formula lie straightforward equations based on load placement. For a concentrated load at the center, deflection equals PL³ ÷ 48EI. When that same weight distributes evenly across the entire length, the formula shifts to 5WL³ ÷ 384EI. Comparing these two scenarios shows that spreading a load out cuts the resulting sag by nearly half for the identical total weight.

The variables in these equations carry vastly different weights in the final result. The Span between supports enters the math as a cube, meaning that doubling the distance between supports multiplies the sag by eight. Similarly, the Depth of the section enters as a cube for rectangular shapes. A framing member turned on its edge is drastically stiffer than the exact same piece laid flat, because depth dictates resistance to bending far more than width does.

Evaluating Stiffness Across Common Materials

Choosing the correct material changes the entire structural outcome. The table below outlines how typical structural configurations compare when subjected to identical spans and loads, highlighting the relationship between cross-sectional geometry, material properties, and resulting sag.

MaterialModulus (psi)Common SectionRelative Stiffness
Steel29,000,000Square TubeHigh
Aluminium10,000,000Square TubeMedium
Douglas Fir1,600,000Solid RectangularLow

When calculating bending stress calculator metrics alongside deflection, remember that building codes prioritize stiffness over raw strength. A beam may easily support a heavy load without snapping, yet still deflect so severely that finishes crack or floors bounce uncomfortably. That is why code requirements enforce strict deflection ratios rather than relying solely on yield strength.

Common Mistakes and Structural Limits

A frequent error during manual calculations involves confusing the clear span with the total length of the member. The span must reflect the exact distance between the interior faces of the supports, not the overall length of the stock. Another common mistake involves ignoring the self-weight of the member itself when calculating heavy or long spans. For light framing, self-weight is negligible, but for massive steel headers or large glulam timber beams, the weight of the member contributes significantly to the total load.

Results derived from standard elastic formulas assume isotropic material behavior, uniform cross-sections, and pinned supports. If your installation involves fixed ends, continuous spans over multiple supports, or eccentric loading conditions, these simple formulas will overestimate the actual sag. For critical load-bearing applications in residential or commercial construction, always verify final sizing with a licensed structural engineer or local building official before purchasing materials or beginning fabrication.

The formula

point load: δ = PL³ ÷ 48EI — distributed: δ = 5WL³ ÷ 384EII for a rectangle is bd³ ÷ 12, so depth enters as a cubespan enters as a cube: twice the span is eight times the sagcodes limit deflection to L/360 or L/240, long before strength is in question

Frequently asked questions

Why does doubling the span increase the sag by a factor of eight?

The mathematics governing structural bending include the span length cubed. When you double the distance between supports, two cubed equals eight, meaning the downward sag multiplies rapidly even if the total weight remains unchanged.

What is the difference between the L/360 and L/240 deflection limits?

The L/360 limit restricts sag to one three-hundred-sixtieth of the span length, which is standard for supporting brittle finishes like plaster or tile to prevent cracking. The L/240 limit is slightly more lenient and is typically applied to general floor framing and standard roof rafters.

Does the width of a rectangular beam matter as much as its depth?

No, depth has a much greater impact on stiffness because it enters the second moment of area calculation as a cube. Doubling the width doubles the stiffness, but doubling the depth multiplies the stiffness by a factor of eight.

How does spreading a load out change the deflection compared to a point load?

Distributing the exact same total weight evenly across the entire length of the span cuts the maximum mid-span deflection nearly in half compared to concentrating that weight at a single point right in the middle.

When should I consult a professional engineer instead of relying on standard formulas?

You should consult a licensed structural engineer whenever your project involves life safety, multi-story load paths, unusual dynamic loads, or composite materials. Standard formulas are ideal for preliminary design and shop fabrication, but permitted construction requires professional sign-off.

Sources

Last reviewed . Results are for general guidance and are not professional advice.