Skip to content
BestCalculators LogoBestCalculators
Free online calculators and converters

Math & Statistics

Free Fall Calculator: Time, Speed and Distance

Work out how long a fall takes, how fast the object is going when it lands, and the distance covered in each second — with and without air resistance.

m

Measured to where it lands. A three-storey building is about 10 m, and a high diving board is 10 m exactly.

Earth’s standard value is 9.80665 m/s². It varies by a few tenths of a per cent with latitude and altitude, which never matters outside a laboratory.

m/s

Zero for a drop. Negative if it is thrown upward first, which adds the climb and the fall back to the same point.

kg

It has no effect on the timing at all — it is used only for the energy and terminal velocity figures.

The silhouette the air sees, for the terminal velocity estimate. A person falling flat is about 0.7 m²; a cannonball is a few hundredths.

Time to fall

2.02s

From v = u + gt solved for t. The mass does not appear anywhere in it, which is the whole point of the experiment on the Moon.

Speed on impact
19.806m/s

√(2gh) for a standing drop. Note the square root: to hit twice as hard you have to fall four times as far.

And in km/h
71.3km/h

A 20 m drop lands at motorway speed, which is the comparison that makes a third-floor window frightening.

In miles per hour
44.3mph
Distance in the first second
4.903m

Just under 5 m on Earth. Compare it with the last second below — the difference is the whole of what "accelerating" means.

Distance in the final second
14.902m

Far more ground than the first second covers, because speed has been building the whole way down.

Time to fall halfway
1.428s

About 71% of the total, not half of it. The second half of the drop takes only 29% of the time, which is why the last part of a fall feels sudden.

Kinetic energy at impact
980.7J

Here the mass finally matters. It is proportional to the height, so twice the drop is twice the energy even though it is only 1.4 times the speed.

Terminal velocity estimate
39.05m/s

Where drag balances weight, at sea-level air density and a drag coefficient near 1. Past this speed the object stops accelerating, and every figure above becomes an overestimate.

Does the fall reach terminal velocity
0

1 means air resistance matters here and the no-drag figures above are too high. 0 means the drop is short or dense enough for them to hold.

Time to reach terminal velocity
3.98s

A rough figure — the true approach is asymptotic, so an object gets close to this speed but never quite reaches it.

Drop that takes exactly one second
4.903m

4.9 m on Earth. It is the fastest sanity check there is: a one-second fall is roughly a storey and a half.

Drop that reaches 100 km/h
39.34m

About 39 m on Earth — roughly a twelve-storey building, ignoring air resistance.

How to use this calculator

  1. Enter the drop height in metres into the Drop height field, measured precisely from the point of release to where the object lands.
  2. Select your target planetary body from the Gravity dropdown menu, using Earth's standard value of 9.807 m/s² for most everyday scenarios.
  3. Enter any Initial downward speed, leaving it at zero for a stationary drop or inputting a negative value if the object is thrown upward first.
  4. Enter the Mass in kilograms, which does not affect the timing but is required for the energy and terminal velocity calculations.
  5. Enter the Frontal area in square metres, representing the silhouette the air sees, to calculate the terminal velocity estimate.

How Falling Objects Behave Under Gravity

When an object drops, it accelerates because gravity pulls it downward at a constant rate. Near the surface of Earth, this acceleration due to gravity is approximately 9.807 m/s², meaning every second it falls, its downward speed increases by about 9.8 metres per second. To find out the exact falling object speed and the total duration, you rely on foundational physics equations that link distance, time, and velocity. The fundamental relationship is expressed as h = ut + ½gt², where height h equals initial speed u multiplied by time t, plus one-half multiplied by gravity g and time squared. Rearranging this formula allows you to calculate the precise time to fall distance without guesswork.

A common point of confusion arises around the mass of the falling body. In a vacuum, a feather and a bowling ball hit the ground at the exact same time because gravity accelerates all masses equally. The mass cancels out of the timing equations entirely, meaning it affects the kinetic energy at impact but never the duration of the fall. However, in the real world, air pushes back against moving objects. This resistance introduces a complexity that the calculator handles by estimating terminal velocity—the maximum speed a falling object can reach when drag balances out the downward pull of gravity.

Calculating Impact Velocity and Timing

To determine how fast an object is moving when it hits the ground, you use the impact velocity calculator formulas embedded in the tool. The speed on impact is found using the square root of the initial speed squared plus twice the gravitational acceleration multiplied by the drop height: v = √(u² + 2gh). This mathematical relationship reveals a crucial insight: impact speed goes with the square root of the height, meaning doubling the drop height does not double your impact speed; it multiplies it by the square root of two, or roughly 1.41.

The tool quietly handles unit conversions, translating metres per second into kilometres per hour by multiplying by 3.6, and into miles per hour by multiplying by 2.2369363. It also breaks down the descent into specific increments, such as the distance covered in the first second and the distance covered in the final second of travel. For a standard drop from rest on Earth, a free fall calculator reveals that an object will drop exactly 4.9 metres in its very first second of flight.

The Hidden Effect of Air Resistance and Terminal Velocity

In an ideal vacuum, objects accelerate indefinitely until they impact a surface. In reality, air molecules collide with a falling object, creating drag force that opposes the motion. The calculator estimates this ceiling using the formula for terminal velocity, defined as √(2mg ÷ ρCdA), where m is mass, g is gravity, ρ is air density, Cd is the drag coefficient, and A is the frontal area. When the upward push of air resistance equals the downward pull of gravity, acceleration stops, and the object continues falling at a steady, unchanging speed.

Drop HeightTime to FallImpact Speed (km/h)Impact Speed (mph)
5 metres1.01 seconds35.7 km/h22.2 mph
10 metres1.43 seconds50.4 km/h31.3 mph
20 metres2.02 seconds71.3 km/h44.3 mph
50 metres3.19 seconds112.7 km/h70.1 mph
100 metres4.52 seconds159.4 km/h99.1 mph

The software evaluates whether your drop actually reaches this aerodynamic ceiling by comparing the calculated vacuum impact speed against the terminal velocity estimate. If the vacuum speed exceeds the terminal velocity, the object reaches its maximum speed mid-air and coasts at that velocity for the remainder of the descent. The calculator also computes the time required to reach that threshold, giving you a complete picture of the physics involved.

Limitations and When to Seek Expert Help

While these mathematical models provide extremely accurate estimates for most engineering, educational, and recreational questions, they rely on standardized assumptions. Atmospheric density is held constant at sea-level standard conditions, and the drag coefficient is approximated for general shapes. For high-altitude skydiving, supersonic freefall, or objects with irregular tumbling aerodynamics, standard physics formulas fail to capture the shifting fluid dynamics. In those advanced aerospace scenarios, computational fluid dynamics software and professional aeronautical engineers must be consulted instead of basic kinematic equations.

A common mistake users make is inputting the wrong units—such as confusing metres with feet, or entering mass in pounds instead of kilograms. This error skews the kinetic energy and terminal velocity outputs dramatically while leaving time calculations unaffected if mass was properly isolated. Always verify your units of measurement before interpreting the final results to ensure your physical safety and numerical accuracy.

The formula

h = ut + ½gt², so t = (√(u² + 2gh) − u) ÷ gv = √(u² + 2gh) — impact speed goes with the square root of the heightthe mass cancels: it affects the energy, never the timingterminal velocity = √(2mg ÷ ρCdA), where drag balances weight

Frequently asked questions

Does the mass of a falling object change how fast it falls?

In a vacuum, mass has zero effect on the timing or speed of a fall because gravitational acceleration acts equally on all objects. In the real world, mass interacts with air resistance, meaning heavier objects with small frontal areas punch through the air more effectively and reach higher speeds before terminal velocity stops their acceleration.

Why does doubling the drop height not double the impact speed?

Impact speed scales with the square root of the drop height rather than a linear multiplier. Because of this square root relationship, you must quadruple the height of a fall to double the final impact velocity when air resistance is ignored.

What is terminal velocity and how does it affect my results?

Terminal velocity is the maximum speed an object can achieve when the upward force of air drag equals the downward pull of gravity. If your drop height is large enough, the falling object stops accelerating and maintains this steady speed until impact, which the calculator flags automatically.

Why does the gravity dropdown include values for Mars and Jupiter?

Different celestial bodies exert different gravitational pulls based on their mass and radius, which changes how quickly objects accelerate toward their surfaces. Selecting Mars or Jupiter lets you instantly recalculate fall times and impact speeds for planetary exploration or physics thought experiments.

Can I use this calculator if the object is thrown upward first?

Yes, by entering a negative value into the initial downward speed field to represent an upward launch. The math will correctly account for the time it takes the object to stop rising at its apex and fall back down past the release point.

Sources

Last reviewed . Results are for general guidance and are not professional advice.